socket.sendto error:

[Ibrahim Salim Omari]

greetings,

when I run the following code:

#!/usr/bin/python3

''' udp socket client Silver Moon '''

import socket   #  for sockets
import sys #  for exit

# create dgram udp socket

try:
    s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
# except socket.error:
except OSError as err:
    print('Failed to create socket')
    sys.exit()

host = 'localhost'
port = 8888

while True:
    msg = input('Enter message to send : ')

    try :
        # Set the whole string and convert encode the string to bytes
        s.sendto(str.encode(msg), (host, port))

        # receive data from client (data, addr)
        d = s.recvfrom(1024)
        reply = d[0]
        addr = d[1]

        print('Server reply : ' + str(bytes.decode(reply)))  # convert reply to string
    except OSError as err:
    # except Exception as err:
        print('Error Code : ' + str(msg[0]) + ' Message ' + str(msg[1]))
        sys.exit()

this line:

s.sendto(str.encode(msg), (host, port))

throws the following error:

ValueError: invalid arguments

the line works on a full python environment. But it doesn't in micropython.
Any suggestions?

iomari

[Gijs]

It took me some time, but the issue is with 'localhost', the micropython expects an IP address there. Other than that, it should work fine once you are connected to a network

Gijs

[Ibrahim Salim Omari]

@Gijs Thanks. It was the localhost. Working fine now with an ip address.