strptime

[Phil]

I believe this function is not available, what is the workaround?

ReportingTimeSTR = "2019-01-01 {}:{}:{}".format(ReportingTime[0:2], ReportingTime[2:4], ReportingTime[4:6])
RT = datetime.strptime(ReportingTimeSTR, '%Y-%m-%d %H:%M:%S')

Thanks

[Phil]

Actually I think I can do what I need by using mktime() :

t = (2009, 2, 17, 17, 3, 38, 1, 48, 0)
secs = time.mktime( t )
print("time.mktime(t) : %f" % secs)

[Phil]

It hands back a proper Time Structure:
typedef struct _timeutils_struct_time_t {
uint16_t tm_year; // i.e. 2014
uint8_t tm_mon; // 1..12
uint8_t tm_mday; // 1..31
uint8_t tm_hour; // 0..23
uint8_t tm_min; // 0..59
uint8_t tm_sec; // 0..59
uint8_t tm_wday; // 0..6 0 = Monday
uint16_t tm_yday; // 1..366
} timeutils_struct_time_t;

Then maybe..., Thanks

[Steve Williams]

@Phil Depending, what you are using it on and how you use the time information, would utime.localtime() give you the information you need? As a tuple it isn't hard to format the returned data into a string.