LoPy with Expansion board, How do you measure LiPo Battery up to 4.2V?

[ledbelly2142]

I am wrapping my head around measuring the battery voltage on pin 16 with the Attn set to '3'. My understanding is that pin 16 with the resistors will output a voltage of 0 to 1.4 that can be interpreted as a voltage from 0 to 3.9V in 4096 steps (attn=3). The BQ24040 on the expansion board (from TI) charges Li-ion batteries with a min and max charge voltage of 4.2V.

Maybe this is more of a math problem with a simple solution.

I am using protected 18650 batteries so they are not left to undercharge by accident, low end Voltage cut off is around 3V I think(haven't tested) and the high end at 4.2V.

If the range is 3V (0%) to 3.9V(100%), there is a 0.9V range of juice. The battery percentage would look something like:

percent_battery = ((meanADC/4096*3.548/0.3275)-3)/0.9

If I want to show a battery charged at 100% (at 4.2 volts) is that possible with the LoPy and expansion board?

Any feedback is appreciated.

[ledbelly2142]

@jmarcelino
Once again, thanks for the great feedback. I was looking for a simple way to alert when the battery needs to be recharged. Looks like some simple logic could be: if voltages gets to 3.3, alert for recharge...

So many LiPo batteries have differing characteristics, even among the same model/make/capacity/manufacturer. I don't think there is real value is tracking a percentage... without extensive battery testing. Simplest thing to do is just report voltage.

From the example from HERE do you recommend using the following:

numADCreadings = const(100)
def ADCloopMeanStdDev():
    adc = machine.ADC(0)
    adcread = adc.channel(attn=1, pin='P16')
    samplesADC = [0.0]*numADCreadings; meanADC = 0.0
    i = 0
    while (i < numADCreadings):
        adcint = adcread()
        samplesADC[i] = adcint
        meanADC += adcint
        i += 1
    meanADC /= numADCreadings
    varianceADC = 0.0
    for adcint in samplesADC:
        varianceADC += (adcint - meanADC)**2
    varianceADC /= (numADCreadings - 1)
    print("%u ADC readings :\n%s" %(numADCreadings, str(samplesADC)))
    print("Mean of ADC readings (0-1023) = %15.13f" % meanADC)
    print("Mean of ADC readings (0-1400 mV) = %15.13f" % (meanADC*1400/1024))
    print("Variance of ADC readings = %15.13f" % varianceADC)
    print("10**6*Variance/(Mean**2) of ADC readings = %15.13f" % ((varianceADC*10**6)//(meanADC**2)))
    print("ADC reading for Voltage (0-1400 mV) = %15.4f" % (meanADC*1400/1024))

From the ACD pin 16 voltage, the voltage is the meanACD*1400/1024
Does not seem right, the output is 4966.3634.

[jmarcelino]

The other thing is lithium batteries are notoriously difficult to estimate in percentage. You wouldn't believe some of complexity of the algorithms the industry uses to make this appear as a nice and easy value for the user.

Take this typical LiPo discharge curve for example

You'll see that it's not linear, from about 90% to 5% the voltage remains almost const and only changes by about 3-5mV per %.

A simple formula like the one you posted would show the battery quickly falling to 50%, remaining around there for a very long time and then when finally dropping to around 40% would mean in reality the device was almost about to die.

[jmarcelino]

@ledbelly2142
First I think it helps if you use the attenuation constants, e.g. ADC.ATTN_11DB instead of arbitrary meaningless numbers like 3.

With ADC.ATTN_11DB the full range of the ADC is 3.9v so ADC reading 0 mean 0 volts and 4095 means 3.9v (but this is just a numeric range, don't feed it over 3.3V!)

The voltage divider on the expansion board "divides" the input voltage so that if the battery is at 4.2v you see ~ 1.4v into the ADC. This means the maximum ADC value - at ATTN_11DB - you would ever read for the battery (when at 4.2v) is 1.4 * 4095 / 3.9 = 1470.

This isn't very good because you're only using 1/3 of the range of the of the ADC , so I'd suggest using a lower attenuation.